結果 : what is the derivative of sin inverse 2x 1 x 2
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Find the derivative of `"sin"^(-1) (2x)/(1+x^(2))` w.r.t. `"tan"^(-1)(2x)/(1-x^(2))`

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Find dy/dx if y = sin^-1 (2x√(1-x²)) | Differentiate sin inverse 2 x into under root 1 - x square

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integration sin inverse 2x /1+x² from 0 to 1

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The derivative of `sin^(-1)((2x)/(1+x^(2)))` with respect to `cos^(-1)((1-x^(2))/(1+x^(2)))` is

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Q19 | Differentiate 〖tan〗^(-1)⁡(2x/(1-x^2 )) w. r. t. 〖sin〗^(-1)⁡(2x/(1+x^2 ))

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Q) If 𝑦=sin^(−1) (2𝑥√(1−𝑥^2 )),, then 𝑑𝑦/𝑑𝑥 is #cbse2026 #maths #cbse #maths #class12math #cbse

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Integration of sin inverse 2x / 1 + x square @StudyPointPro

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show that (i) sin-1(2x√(1-x^2))=2sin-1 x and (ii) sin-1(2x√(1-x^2))=2cos-1 x

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