Find dy/dx if y = tan^-1(3x-x³/1-3x²) | Differentiate of tan inverse 3x minus x cube by 1 minus 3x

Find 'dydx' of 'y= tan^–1[(3x-x^3)/(1-3x^2)]' , -1√3 less than x less than 1√3

tan-1[(3x-x^3)/(1-3x^2)] | Inverse function | Derivation

ITF - [NCERT ] - Ex #6 Prove : tan^-1 [3x - x^3/1- 3x^2 ]=tan^-1 x+tan^-1( 2x/1-x^2 ) [ ALLAHABAD]

Q11 | Differentiate tan^(-1)⁡((3x-x^3)/(1-3x^2))

`tan^(-1)((sqrt(x)(3-x))/(1-3x))`

y=tan^(-1)((3x-x^3)/(1-3x^2))。dy/dxを求めよ。| クラス11 | 極限と微分 | 数学 | 疑問...

Derivatives of Inverse Trigonometric Functions

Integrate x^2/(2+3x^2)^3 | #NCERT Class-XII | Exercise 7.2 Q13 #Integration | #cbseclass12

Find dy/dx if y = tan-1(3x-x3)/1-3x2 . If y = sin -1 (x square root 1-x -

14. Derivative Find dy by dx of y = tan -1( 3x-x3 upon 1-3x2)

Class12-EX4.5-(10)|Find no. of solution of tan-1(x-1)+tan-1(x)+tan-1(x+1)=tan-1(3x)|

find dy/dx,if y=tan^-1(3x-x^3/1-3x^2)|differentiation

Differentiate y=tan^-1(3x-x^3/1-3x^2)

`int tan^(-1) ((3x-x^3)/(1-3x^2))dx`

Derivative of sin ^-1(3x+4) || Differentiation of inverse trigonometric functions

Find `(dy)/(dx)`in the following:`y=tan^(-1)((3x-x^3)/(1-3x^2)),-1/(sqrt(3))ltxlt1/(sqrt(3))`

Prove that 3tan-1 x = tan-1 (3x − x3)/(1 − 3x2)

Derivatives of inverse trigonometric functions sin-1(2x), cos-1 (x^2), tan-1 (x/2) sec-1 (1+x^2)

Differentiating Inverse Tan for A-Level | Derivative of Tan-1x or arc tan x