Calculus, derivative of inverse tangent

Q11 | Differentiate tan^(-1)⁡((3x-x^3)/(1-3x^2))

Derivative of y = (1/3)tan^(-1)(x/3)

y = tan^-1{(3x - x^3)/ (1-3x^2)} Find dy/dx | Differentiation | CalculusCheck | NCERT

tan-1[(3x-x^3)/(1-3x^2)] | Inverse function | Derivation

Derivative of tan inverse with chain rule

Find dy/dx if y = tan^-1(3x-x³/1-3x²) | Differentiate of tan inverse 3x minus x cube by 1 minus 3x

Differentiate y=tan^-1(3x-x^3/1-3x^2)

Differential Equations Class 12 | Part 2 | One Shot in English | JEE Main & Advanced

find dy/dx,if y=tan^-1(3x-x^3/1-3x^2)|differentiation

14. Derivative Find dy by dx of y = tan -1( 3x-x3 upon 1-3x2)

Mastering Calculus: Derivative of Inverse Tangent Function [𝑡𝑎𝑛^(−1) ((3𝑥−𝑥^3)/(1−3𝑥^2 ))] Explained

Derivatives of Inverse Trigonometric Functions

Derivatives of inverse trigonometric functions sin-1(2x), cos-1 (x^2), tan-1 (x/2) sec-1 (1+x^2)

y=`tan^(-1)((3x-x^(3))/(1-3x^(2)))`Find dy/dx

If ` y=tan n^(-1) ((sqrtx(3-x))/( 1-3x) ) ,then (dy)/(dx) =`

Find 'dydx' of 'y= tan^–1[(3x-x^3)/(1-3x^2)]' , -1√3 less than x less than 1√3

Derivative of tan^-1(e^x) || Differentiation of inverse trigonometric functions

`tan^(-1)((3x-x^(3))/(1-3x^(2)))`

If y=tan^-1[3x-x³]/[1-3x²],-1/√3 lessthan x lessthan 1/√3,then find dy/dx