結果 : what is the formula for cot inverse a cot inverse b
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Cot(A+B)=(cotAcotB -1)/(cotB +cotA), cot(A-B) =(cotAcotB +1)/(cotB-cotA)

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The sum of infinite terms of the series cot^-1(1^2+3/4)+cot^-1(2^2+3/4)+cot^-1(3^2+3/4)+.....infinte

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