結果 : what is the value of log x base 2

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異なる底を持つ対数方程式を解きます | log_2(x) + log_5(x)= 4。

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Logarithm solved example (Mathematics)| Solve : log x(base 2) + log x(base 4) = 2 |

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If log x to the base 2 + log x to the base 4 + log x to the base 16 = 7/2, find the value of x.

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Find number of solutions of log[base 4] (x-1) = log[Base 2] (x-3).

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1. Set of all values satisfying x^log (1-x)^2 base x = 9 | 2. log 5 base 5+ log 5^2 base 5+

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