`x^(3)-3x^(2)-9x-5`を因数分解します。
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Factorise x3-3x2-9x-5| | Factorise x cube -3xsquare-9x-5 ||Factorise x3-3x2-9x-5 By Factor Theorem |
多項式の因数を求めよ。x^(3) - 3x^(2) - 9xのとき、5の因数は(x-5)である。| 9 | 多項式の性質。
गुणनखंड ज्ञात कीजिए:x ^ 3 - 3x ^ 2 - 9x - 5
因数分解: (i) `x^3-2x^2-x+2` (ii) `x^3-3x^2-9x-5` (iii) `x^3+13 x^2+32 x+20` (iv) `2y^3+y^2-2y-1`
x^3-3x^2-9x-5 का गुणनखंड निकालें || x3-3x2-9x-5 का गुणनखंड निकालें || x3-3x2-9x-5 || x^3-3x^2-9x-5
Factorize x3-3x2-9x-5, Factorise x3-3x2-9x-5
Factorise x³-3x²-9x-5
Factorise x3-3x2-9x-5 | Factorise x Cube Minus 3 x Square - 9 x Minus 5 | Factorise x^3-3x^2-9x-5
Factorize : x^3 – 3x^2 – 9x – 5#mathsclass9
Polynomials Class 9th Ex 2.3 Q5(ii) Factorise x3 - 3x2 - 9x - 5 | Factorisation by Factor Theorem
x^3-3x^2-9x-5 | を因数分解します。多項式 |例 2.4 クラス 9 [Q5 (ii)]
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