find the root of the following equation using factorisation method. X^2+5x+6=0.

Show that the equation `x^(2)+5x-6=0` has real roots.

x^2 - 5x + 6 = 0 を因数分解で解く方法

二次方程式 x^2 + 5x - 6 = 0 を解かずに根の和と積を求めます。

x^2-5x+6=0 | Lets Know The Quick Solution

二次方程式: x^2 - 5x + 6 = 0 を解く

alpha and beta roots of quadratic equation | Finding new equation

4x^2-5x-6=0 | Find The Discriminant & Roots

IF 4x^2-5x-6=0 Then X=? | Learn the Trick to Solve Quickly

Solve by completing the square | Step by Step Technique

Finding the Discriminant and Nature of Roots | Explain in Detailed |

二次方程式 x^2 + 5x + 6 = 0 「X」の場合 | を解きます。驚くべきトリックを学ぶ

Solve quadratic equation by factorisation

判別 - 二次方程式の根の性質 @MathTeacherGon

Find the nature of the roots of the quadratic equationx^2-5x+9=0

x^2+5x+6=0 | Find The Discriminant & Roots

Graph/Find the turning point of the quadratic function

|#CLASS10| |QUADRATIC EQUATION ||#x^2+5x-(a+1)(a+6)=0 |#@Maths with shimna|

Find the nature of the roots of the following quadratic equations. If real roots exist, find them...

The number of real roots of the equation 2 x^4+5 x^2+3=0, is 👇