`ysin2xdx-(1+y^2+cos^2x)dy=0`

Q166 (ysin2x)dx - (1+y^2+cos^2(x))dy = 0

(ysin2x)dx-(y^2+cos^2x)dy=0 #ExactEquation L504 @MathsPulseChinnaiahKalpana

solve (ysin2x)dx-(1+y^2+cos^2x)dy=0 || BS Grewal problem 11.7 Question number 09 || #trending

Q184 Solve ysin2x dx = (1+y^2 + cos^2(x) ) dy

Q167 Solve (ysin2x)dx - (y^2 + cos^2x)dy = 0

微分方程式「(1 + cos 2x) + (1- cos 2y) (dx)/(dy) = 0」を解きます。

微積分ヘルプ: 厳密な微分方程式 - ( y^2 sin2x )dx+(1-ycos^2 x) dy=0

😳 きれいな基本微分 d/dx(sin2x)=? を微分します。 #ショートパンツ

`(2x -2y+3) dx -(x-y+1) dy=0 , " x=0, y=1 のとき `

Differential Equations Practice #42: cosysin2xdx + (cos^2(y) - cos^(x))dy = 0

Q185 Solve (x^3 + xy^2 + a^2y)dx + (y^3 + yx^2 - a^2x)dy = 0

If y = `(sinx-xcos x)(cosx +xsin x)`, show that ` dy/dx=x sin2x-x^2 cos 2x`

IIT JEE DIFFERENTIAL EQUATIONS Solution of the equation `cos^2x(dy)/(dx)-(tan2x)y=cos^4x ,|x| lt ...

Q196 Solve (y+cosy + 1/2√x)dx + (x-xsiny - 1)dy = 0

Find the solution of the differential equation `{y(1+1/x)+siny}dx+(x+lnx+xcosy)dy=0`

General solution of `e^(x)cotydx+(1-e^(x))cosec^(2)ydy=0` is

Exact Differential Equation | x(x^2+y^2-a^2)dx + y(x^2-y^2-b^2)dy = 0

The solution of the differential equation `sinxcosy dy + cosx siny dx= 0` is

{y(1+log x) + cos x}dx + {x + logx - x siny}dy =0