三角関数の置換積分 sqrt(x^2 - 16)/x

微積分ヘルプ: ∫√(16-x^2)dx の積分 - 三角関数の置換による積分

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微積分ヘルプ: ∫ x^2/√(16-x^2 ) dx の積分 - 三角関数置換による積分 - 解決済み!

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