微積分ヘルプ: ∫√(16-x^2)dx の積分 - 三角関数の置換による積分
三角関数の置換積分 sqrt(x^2 - 16)/x
integral of 1/sqrt(16-x^2) dx
微積分ヘルプ: ∫ x^2/√(16-x^2 ) dx の積分 - 三角関数置換による積分 - 解決済み!
integral of 1/sqrt(x^2+16)
Integral 42: int 1/[x^2 sqrt(16 x^2)} dx
Integrate | 1/sqrt(16-x^2) dx
Calculus Help: Integral of (x^3 dx)/√(16-x^2 ) - Integration by substitution
Integral of dx/sqrt(16+4x-2x^2) - (U substitution + Trigonometric Substitution)
Integration of square root of 16 minus x square, int(sqrt(16-x^2)).
Learn to evaluate using the definite integral with square root
INTEGRATION BY TRIGONOMETRIC SUBSTITUTION | PART 2
Calculus Help: ∫ dx/(x√(16x^2-1)) - Integration by trigonometric substitution - Techniques
Integral of 1/sqrt(16 - x^2) dx using trigonometric substitution
Integral of 1/sqrt(16 - x^2)
`int(dx)/(sqrt(16-x^(2)))`
微積分ヘルプ: dx/(x√(x^2-16)) の積分 - 置換積分
integral of sqrt(x^2+2x), trig substitution, calculus 2 tutorial.
find integral of square root of 16+(log x)^2/x dx
How to Integrate square root of x