計算コット(3π/2)

'cos(3pi2 + x) cos(2pi + x )[ cot(3pi2- x) + cot(2pi + x)] = 1'||

cot(3π/2-x)=?,Trigonometry,m aths,class-11,General aptitude,cot(2π-x),cot(π/2+x)

prove that cos(3π/2+x)cos(2π+x)[cot(3π/2-x)+cot(2π+x)]=1|| Worldeez Academy

10+1,Trigo.funts.of type Cot(3π/2+x)=-Tanx

ベビーベッド(3pi/2)

Prove that : sec (3π/2 - x) sec(x - 5π/2) + tan(5π/2 + x) tan((x - 3π/2) = -1

Show that cos(3π/2 + x) cos(2π + x){ cot(3π/2 -x) + cot(2π +x) } = 1

cos(3π/2 + x) cos(2π + x)[ cot(3π/2 - x) +cot(2π +x) ] =1cos(π+θ)cos(-θ)/sin(π-θ)cos(π2+θ)=cot^2 θ

`cos((3π)/(2) +x) cos(2π+x)[cot(3π)/(2)-x+cot(2π+x)]=1`

The value of cos^2⁡〖π/16+cos^2⁡〖3π/16+cos^2⁡〖5π/16+cos^2⁡〖7π/16〗 〗 〗 〗...👇

Find x, If tan^-1(√3)+cot^-1(x)=π/2|Inverse Trigonometric Functions|Class-12|Maths|Aptitude|Diploma

Ex 3.3 Q9 cos(3π/2+x) cos (2π+x )[ (cot(3π/2 - x)+ cot (2π +x) = 1

If csc𝜃 = 8/3 & π/2＜𝜃＜π, find cot(𝜃/2).

9. cos(3π/2+x) cos⁡(2π+x) [cot⁡(3π/2-x)+cot⁡(2π+x) ]=1

cos.((3pi)/2+x)cos.(2pi+x) [ cot((3pi)/2-x)+cot(2pi+x)]=1 | 11 | 三角関数 | 数学 |...

cos((3pi)/(2)+theta)cos(2pi+theta)[cot((3pi)/(2)-theta)+cot(2pi+theta)]=1 | 11 | であることを証明してください。

Cos(3π/2+x)Cos(2π+x) [Cot(3π/2-x)+Cot(2π+x)] =1. Easily Proved By A.K. SINHA #DARPANACADEMY #AKSINHA

sin(π/2 + θ) × cos(3π/2 + θ) × tan(5π/2 + θ) × cot(7π/2 + θ) | Trigonometry Shortcutcom

Prove that cos(3π/2+x)cos(2π+x)[cot(3π/2-x)+cot(2π+x)]=1|Trigonometry|Class 11|12th|Maths|Aptitude