cot(3π/2-x)=?,Trigonometry,m aths,class-11,General aptitude,cot(2π-x),cot(π/2+x)
cot(270 + x) | cot(3pi/2 + x) | cot(270 + A) | cot(3pi/2 + A) | cot(270 + theta)
'cos(3pi2 + x) cos(2pi + x )[ cot(3pi2- x) + cot(2pi + x)] = 1'||
9. Prove that cos (3pi/2 + x) cos (2pi + x) { cot (3pi/2 - x) + cot (2 pi +x)} =1
9. cos(3π/2+x) cos(2π+x) [cot(3π/2-x)+cot(2π+x) ]=1
Simplify the expression cos (x - 3pi/2). Sum and Difference Formula. Trigonometry
Prove that: `cos((3pi)/2+x)cos(2x+x)[cot((3pi)/2-x)+cot(2pi+x)]=1`...
Establish sum and difference identity sin(3pi/2 + x) = - cos x
`cos((3pi)/(2) +x) cos(2pi+x)[cot(3pi)/(2)-x+cot(2pi+x)]=1`
cot(270 – x) | cot(3pi/2 – x) | cot(270 – A) | cot(3pi/2 – A) | cot(270 – theta)
If cos x = (- sqrt(3))/2 and pi x (3pi)/2 then the value of 4cot^2 x - 3cos e * c ^ 2 * xis:
Cofunction Trigonometric Identity Explanation sin(3pi/2 - x)
cos(3pi/2 - x) | cos(3pi/2 - theta)
cos((3pi)/(2)-x) は次式に等しい: | クラス 11 | 三角法 | 数学 | ダウトナット
prove cos(x - 3pi/2) = -sinx
Prove that : sec (3π/2 - x) sec(x - 5π/2) + tan(5π/2 + x) tan((x - 3π/2) = -1
TRIGONOMETRIC FUNCTIONS CLASS 11 EX 3.3 Q 9 NCERT CBSE ISC IIT JEE IMPORTANT QUESTIONS SOLUTIONS
sin(3pi/2 - x) | sin(3pi/2 - theta)
Compute csc(3pi/2)
Verify the Trigonometric Identity cos(3pi/2 - x) = -sin(x)