結果 : integrate log sin 2x dx from 0 to pi 2

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 ∫ log(sin 2x)dx from 0 to π/2 = -π/2(log2)

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Integration log sin2x dx prove that -pi by 4 log2 | Integral of log sin2x from 0 to pi/4 |

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Q10 | Integration of 2 log sin x minus log sin 2x | Integrate 0 to π/2 of 2log(sinx)-log(sin2x)

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Show that `int_0^(pi/2) log(sin 2x) dx=-pi/2 (log2)`.

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integrate [log(sin x) - log(2cos x)] dx from 0 to pi/2

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int_(0)^(pi//2) [2log sin x-log sin 2x] dx= | クラス 12 | 定積分 | 数学 | ダウトナット

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Q43 | Integral 0 to pi/2 sin 2x log tan x dx | Integrate sin 2x log tan x dx from 0 to pi/2

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integrate log Sin x from 0 to pi/2

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The value of `int_(0)^(pi//2) (2log sin x-log sin 2x)dx`, is

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