`intsqrt(x^2-4x-5)dx=`
Integrate the function ∫ root over x^2+4x-5 dx
Q54、sqrt(x^2+4x+5)の積分、平方完成した三角積分
sqrt(x^2+4x+5)の積分
`sqrt(x^(2)+4x-5)`
2. Integrate: (x) ∫ x dx/√(x² + 4x + 5) int xdx/sqrt(x²+4x+5) Antiderivative Calculus "MSI" NEB 12💥🌻
7. Integrate ∫ √(4x²–4x +5) dx, int sqrt(4x²–4x+5)dx Antiderivative calculus Math Star Industries💥🌻
(x-2)/(x^2-4x+5) の積分 - 積分の例
Integrate(sqrt (5-4x-x^2 ))
10. ∫ (x–1)√(5–4x–x²) dx Integrate (x–1) sqrt(5–4x–x²) Antiderivative calculus Math Star Industries🌻
`int(dx)/(x^2+4x-5)=`
#Integrals || Evaluate integral of (3x-2) by \sqrt{4x^2-4x-5} dx
Integrate (5x+1)/(2x²+4x+3) wrt x
2. Integrate: (iii) ∫ dx/√(x²+4x–5) int dx/sqrt(x²+4x–5) Antiderivative Calculus "MSI" NEB 12 💥🌻
Calculus Help: Integral dx/(x^2-4x-5) - Integration by partial fractions - Techniques
Integration of Rational Functions By Completing The Square - Calculus
11th Std Maths Ex.11.10(3)(ii) Integrate 1/√ x²-4x+5
Integral of (x+1)/sqrt(x^2+2x+5) (substitution)
ax^2+bx+c の平方根の積分に基づく問題 || x^2-4x-5 dx の積分
積分 (x + 2)/sqrt(x^2 + 4x - 6)