Show that by using Vector Method x/a + y/b = 1 is the equation of a straight line in Intercept Form

Deriving Intercept form of Straight Line x/a+y/b=1 | Kamaldheeriya

if p is the perpendicular distance from origin to line x/a+y/b=1 then show that (1/p^2)=1/a^2+1/b^2.

A Variable straight lines passes through the point of intersection of lines x/a + y/b =1 and ….

reduce x/a+y/b=1 to normal form.show x/a^2+y/b^2=1/p^2 here p is perpendicular distance from origin

86 No.:If 1/a+1/b+1/c=1/(a+b+c),show that 1/a^7 +1/b^7 +1/c^7 =1/(a+b+c)^7 =1/(a^7+b^7+c^7 )

x/a=y/b=z/c の場合、(x^3+a^3)/(x^2+a^2)+(y^3+b^3)/(y^2+b^2)+(z^3+c^3)/(z^2+c^2)=((x+y... であることを示します。

If 2s=a+b+c,show that 1/(s-a)+1/(s-b)+1/(s-c)-1/s=abc/s(s-a)(s-b)(s-c).

Q1:Extra Geometry #@ganitshiksha1220 #@p_maitysir

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Show that x/a+y/b=1 touches the curve y=b e^-x / a at the point, where the curve crosses the y-ax...

lf (x + iy)^1/3 = a + ib then x/a + y/b =

The area of triangle formed by the line x/a+y/b=1 with coordinate axes is...|| MCQ RD Class 10 ||

If the line x/a +y/b =1 passes through the point of intersection of the lines x+y=3.....find a and b

線 x/a+y/b=1、x/b+y/a=1、および y=x が点で交わることを示します。

Prove that the line x=ay+b , z=cy+d and x=a'y+b ,z=c'y+d are perpendicular if aa'+cc'+1=0

If P(x, y) is any point on the line segment joining the points A(a, 0) and B(0, b), then show that x

If `(x+i y)^(1//3)=a+i b ,x ,y ,a b in Rdot` Show that `x/a+y/b=4(a^2-b^2)` (ii) `x/a-y/b=2(a^2+...

Reduce x/a + y/b = 1 in perpendicular ferm and show that 1/(a ^ 2) + 1/(b ^ 2) = 1/(p ^ 2)

If (x+ iy)1/3= a + ib, where x, y, a, b ∈ R, show that x/a- y/b = – 2 (a2 + b2