線形三角方程式を次の形式で解きます: 2sin(x)+1=0
Solve for all values of x when 2 sin x +1 =0 over [0, 360]
2*sin(x) - 1 = 0 を [0, 2pi) で解く
三角方程式を因数分解で解く: 2sin^2(x)-sin(x)-1=0 (ラジアン)
Solve the Trig equation 2 sin x +1 = 0 on the interval [0, 2pi)
2sin^2(x) + 3sin(x) + 1 = 0 を解く
Solving Trigonometric Equations, 6sin^2x+sinx-1=0, How to Solve Trigonometric Equations
Trigonometry, polynomials: how to solve equation 2sin(x)^2 - 2sin(x) - 1 = 0
もっと! |ハンター×ハンター 36巻 初見リアクション
Solve the equation 2sin^2(x)-sin()x-1=0 and find the values of x on [0,2π).
Solve the equation 2 sin^2 x + 3 sin x + 1 = 0
Solve the Trig equation 2 sin^2 x -1 = 0 on the interval [0, 2pi)
Solve the Trig equation 2 sin^2 x - sin x - 1 = 0 on the interval [0, 2pi)
解決: 2cos ^2(x)+sin(x)-1=0、4 分で完了、きちんと入力
Solving Trigonometric Equations, 2sin^2x+sinx-1=0, How to Solve Trigonometric Equations
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Solving Trigonometric Equations 2sin^2x-sinx-1=0, How to Solve Trigonometric Equations
HOW TO SOLVE THE TRIGOOMETRIC EQUATION 2sin (x+30)=1 for the range between 0^0 & 360^0 included.
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